Find the complement of the following
A(B'C'+BC)
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Answer:
A(B'C'+BC)
Complement the expression
= A(B'C'+BC)'
Apply Demorgan's first law.
= (A)'+(B'C')' (BC)'
Apply Demorgan's second law
= A'+(B+C) (B'+C')
We can simplify the expression as below
Apply Distribution law (Multiplying out)
= A'+BB'+BC'+CB'+CC'
Apply the complement law
= A'+0+BC'+CB'+0
Apply Identity law
= A'+BC'+B'C
Explanation:
= A'+(B+C)(B'+C') is the answer. But we can simply further using boolean as indicated in the answer.
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