Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠C=46°, and DB = 6.9 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

Question :- In ΔBCD, the measure of ∠D=90°, the measure of ∠C=46°, and DB = 6.9 feet. Find the length of BC to the nearest tenth of a foot. ?

Solution :-

from image we have, in right ∆BDC ,

→ sin 46° = BD / BC

→ sin 46° = 6.9 / BC

→ 0.72 = 6.9 / BC

→ 0.72BC = 6.9

→ BC = 6.9/0.72

→ BC = 6900/720

→ BC = 690/72

→ BC = 9.58

→ BC = 9.6 feet . (Ans.)

Hence, the length of BC is 9.6 feet.

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