Question

Find the complex conjugate of 4i-1, 3-i,-f-i

Answer 1

Answer :

Step - by - step :

(x − [1 + 2i])(x − [1 − 2i]) = x

2 − x[1 − 2i] − x[1 + 2i] + [1 − 2i][1 + 2i]

= x

2 − x + 2ix − x − 2ix + 1 − 2i + 2i − 4i

2

= x

2 − 2x + 5