Physics, asked by offorsomto50, 9 hours ago

Find the component of 2i + 3j + k in the direction of 3i - j
(a) 3/10
(b) √10 / 10
(c) 3√10/10
(d) 3√10

Answers

Answered by storiesinhindighost
1

Answer:

(C)

Solution

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Step 1: Calculation of component of

a

along

i

^

+

j

^

Let

b

=

i

^

+

j

^

The unit vector

b

^

b

^

=

i

^

+

j

^

i

^

+

j

^

=

2

1

(

i

^

+

j

^

)

Component of vector

a

along

b

vector

=acosθ

=a

∣ab∣

a

.

b

=

b

a

.

b

=

a

.

b

^

To get the vector form, (

a

.

b

^

)

b

^

=[(2

i

^

+3

j

^

).

2

1

(

i

^

+

j

^

)]

2

1

(

i

^

+

j

^

) =[

2

1

(2+3)]

2

1

(

i

^

+

j

^

)

=

2

5

(

i

^

+

j

^

)

Step 2: Component of

a

along

i

^

j

^

Let

c

=

i

^

j

^

Unit vector,

c

^

=

2

1

(

i

^

j

^

)

Component of vector

a

along

c

vector

=(

a

.

c

^

)

c

^

=[(2

i

^

+3

j

^

).

2

1

(

i

^

j

^

)]

2

1

(

i

^

j

^

) =[−

2

1

]

2

1

(

i

^

j

^

)

=

2

−1

i

^

+

2

1

j

^

Explanation:

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