find the compound interest at the of 10% for 3 year on that principal which in 3 year at 10% p.a give rs 2400 as simple interest .
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S.I=P×R×T/100
Rs 2400= P×10×3/100
Rs2400 ×100=30×P
Rs240000/30=P
P=Rs 8000
Now,
P=Rs8000
R=10℅
T=3yrs
A=P(1+R/100)^T
=Rs8000(1+10/100)^3
=Rs8000×(11/10)^3
=Rs 8000×1331/1000
=8×1331
=Rs10648
so , c.i.=A-P
=Rs(10648-8000)= Rs2648
Rs 2400= P×10×3/100
Rs2400 ×100=30×P
Rs240000/30=P
P=Rs 8000
Now,
P=Rs8000
R=10℅
T=3yrs
A=P(1+R/100)^T
=Rs8000(1+10/100)^3
=Rs8000×(11/10)^3
=Rs 8000×1331/1000
=8×1331
=Rs10648
so , c.i.=A-P
=Rs(10648-8000)= Rs2648
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