Secularism with reference of jiddu krishnamurti
Answers
Erving Goffman was a sociologist who created a new field of study called microsociology, or social interaction. Social interaction is the process by which we act and react to those around us. In a nutshell, social interaction includes those acts people perform toward each other and the responses they give in return. Having a quick conversation with a friend seems relatively trivial.
Goffman argued that these seemingly insignificant forms of social interaction are of major importance in sociology and should not be overlooked. Social interactions include a large number of behaviors, so many that in sociology, interaction is usually divided into five categories.
=>Amount after n years is given by
a = p \: {(1 +\frac{r}{100 })} ^{n}a=p(1+
100
r
)
n
=>Compound interest = (amount)–(principal)..
=>If the rates be p%, q% and r % during the 1st , 2nd and 3rd year respectively ...then ,
amount \: after \: 3 \: years \:amountafter3years
= p(1 + \frac{p}{100} )(1 + \frac{q}{100})(1 + \frac{r}{100} )=p(1+
100
p
)(1+
100
q
)(1+
100
r
)
=>If the principal = Rs . P , rate = R% per annum and the time = n years , then
[i] amount after n years ( compounded annually)
= rs. \: p(1 + \frac{r}{4 \times 100} )^{n}=rs.p(1+
4×100
r
)
n
[ii] amount after n years ( compounded half yearly )
= rs. \: p \: (1 + \frac{r}{2 \times 100} ) \: ^{2n} ...=rs.p(1+
2×100
r
)
2n
...
[iii] amount after n years ( compounded quarterly)
= rs. \: p \: (1 + \frac{r}{4 \times 100}) ^{4n} .....=rs.p(1+
4×100
r
)
4n
.....
=>If the present population of a place is P and it's increase at the rate of R% per annum ..then,
[I] Population after n years ..that is
= p(1 + \frac{r}{100} )^{n..}=p(1+
100
r
)
n..
[II] population after n years ago
= \frac{p}{(1 + \frac{r}{100}) ^{n....} }=
(1+
100
r
)
n....
p
=> If the present population of a place is P and it decrease at R % per annum , then
Population after n years
= p(1 - \frac{r}{100} ) ^{n}=p(1−
100
r
)
n
=>Suppose If the present population value of a machine is Rs. P and it depreciates at the rate of R% per annum then it's value after n years ...
= rs.p \: (1 - \frac{r}{100})^{n}=rs.p(1−
100
r
)
n
THESE ARE THE FORMULA OF CALCULATING COMPOUND INTEREST .....