Find the compound interest at the rate of 10% per annum for 2 years on the principle which in 2 years at the rate of 10% per annum yields rupees 200 as simple interest
Answers
Answered by
15
For simple interest:
t = 2years
r = 10%
I = 200
Let principal = P
we know
⇒
Compound interest:
r = 10%
t = 2years
P = 1000
n = 1

Compound Interest = A - P = 1210 - 1000 = Rs. 210
t = 2years
r = 10%
I = 200
Let principal = P
we know
⇒
Compound interest:
r = 10%
t = 2years
P = 1000
n = 1
Compound Interest = A - P = 1210 - 1000 = Rs. 210
Similar questions