Question

Find the compound interest, correct to the
nearest rupee, on * 2,400 for 2 years at
5 percent per annum.​

Answer 1

Answer:

yes

Step-by-step explanation:

Because our compound wall is strong

Answer 2

P= Principal=2400

R= Rate of interest=5%

n = Number of years=2 years

$A= P(1+ \frac{R}{100} ) ^{n} \\ \: \: \: = 2400(1 + \frac{5}{100} ) ^{2} \\ \: \: \: = 2400( \frac{105}{100} )^{2} \\ \: \: \: = 2400( \frac{21}{20} )^{2} \\ \: \: \: = 2400 \times \frac{21}{20} \times \frac{21}{20} \: \: \: = 2646$

Compound Interest= A-P =(2646-2400) ₹= ₹246