find the compound interest if p= 4000,n= 3years , r = 5p.c.p.a
Answers
Answer:
(1) Here, P = ₹ 2000; R = 5 % ; N = 2 years
A=P(1+
R
100
)N =2000(1+
5
100
)2 =2000(
105
100
)2 =2000(
21
20
)2 =2205 Rupees∴ Compound Interest after 2 years,I = Amount - Principal =2205-2000 =205 Rupees
Hence, Amount = ₹ 2205 and Compound interest = ₹ 205.
(2) Here, P = ₹ 5000; R = 8 % ; N = 3 years
A=P(1+
R
100
)N =5000(1+
8
100
)3 =5000(
108
100
)3 =5000(
27
25
)3 =6298.56 Rupees∴ Compound Interest after 3 years,I = Amount - Principal =6298.56-5000 =1298.56 Rupees
Hence, Amount = ₹ 6298.56 and Compound interest = ₹ 1298.56
(3) Here, P = ₹ 4000; R = 7.5 % ; N = 2 years
A=P(1+
R
100
)N =4000(1+
7.5
100
)2 =4000(1+
75
1000
)2 =4000(
1075
1000
)2 =4000(
43
40
)2 =4622.50 Rupees∴ Compound Interest after 2 years,I = Amount - Principal =4622.50-4000 =622.50 Rupees
Hence, Amount = ₹ 4622.50 and Compound interest = ₹ 622.50
Step-by-step explanation:
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Answer:
hi mate this your answer,
Amount = ₹4622.50
C.I = ₹662.50
Step-by-step explanation:
C.I is compound interest