Find the compound interest of RS. 12000 for 2 years at 10% per annum compounded annually.
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Answered by
2
•●○ ANSWER ○●•
GIVEN :-
P = 12,000 Rs.,
n=2 years,
R=10
TO FIND :-
Compound Interest.
SOLUTION :-
Amount(A) = P(1+R/100)ⁿ
=12000(1+10/100)²
=12000(11/10)²
=12000 × 121/100
=14,520 Rs.
Compound interest(C.I) =A−P
= 14,520 − 12,000
= 2520
Hence, the compound interest is Rs. 2,520
Answered by
0
Answer:
2520
Step-by-step explanation:
1st year intrest
p=12000
r=10%
t=1
I=P×T×R/100
=12000×1×10/100
=1200
2nd year intrest
P=12000+1200=13200
T=1
R=10%
I=P×T×R/100
=13200×1×10/100
=1320
Total compound interest =1200+1320=2520
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