Find the compound interest on ₹ 1000 at 8% per annum for 1whole1/2 years, while the inrerest compounded half yearly...
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vikku2019:
bro its not answer plz try it again
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A = P {1 + (R/100)}^N and CI = A - P
R = 8/2 = 4 as CI is being calculated half yearly.
N = 3 as 1 whole 1/2 years contain 3 half years.
A = 1000 {1 + (4/100)}^3
= 1000 * 1.124864
= 1124.864
R = 8/2 = 4 as CI is being calculated half yearly.
N = 3 as 1 whole 1/2 years contain 3 half years.
A = 1000 {1 + (4/100)}^3
= 1000 * 1.124864
= 1124.864
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