Question

find the compound interest on 11 200 at 9 per annum for two year

Answer 1

Hey mate here is your answer.

P=11200
R=9
T or n=2years

A=P×[1+R/100] bracket ka Power 2
A=11200×[1+9/100]. ,,. ,,
A=11200×[100+9/100] ,, ,,
A=11200×[109/100] bracket ka Power 2
A=11200×109/100×109/100
A=11200×11881/10000
A=12×11881/100
A=6×11881/50
A=3×11881/25
A=35643/25
A=1425.8

CI=P+A
CI=11200+1425.8
CI=12625.8. * ANSWER*

I Hope It Help You.