Question

find the compound interest on 25000 rate of 12% per annum for 3 years​

Answer 1

Answer:

I=Pnr

or,I=25000×3×12%

or,I=9000

Answer 2

Answer:

10123.2

Step-by-step explanation:

1st year CI = 1+1+1

= 25000*12*1/100

= 3000

1st year Interest 3000

principal= 25000

A= P+I

= 25000 + 3000

= 28000

2nd year CI = P*R*T/100

= 28000*12*1/100

I = 3360

P= 28000+3360

= 31360

3rd year CI = P*R*T/100

= 31360*12*1/100

= 31360+3763.2

= 35123.2

= 35123.2 - 25000

= 10123.2

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