Question

find the compound interest on a sum of Rs 10,000 at 10% interest per annum for 3 years compounded annual ly​

Answer 1

Answer:

Step by step explanation :

P = ₹ 10,000

r = 10% = 0.1

n = 1 (Annually)

t = 3

Compound Interest =

$p(1 + \frac{r}{n} )^{nt}$

$10000(1 + \frac{0.1}{1} )^{1 \times 3}$

10000 ( 11 / 10 )³

10000 × 1331 / 1000

₹ 13,310

Therefore Compound Interest is ₹13,310

Total Principal Amount is ₹ 23,310

Mark Brainliest

@manishthakur100

Answer 2

Given :-

• Principal (p) = Rs 10,000

• Rate (R) = 10% per annum

• Time (t) = 3 years

To find :-

• Compound Interest (CI) = ?

Solution :-

$\rm\:Amount\:(A)=P\bigg(1+\dfrac{R}{100}\bigg)^t$

$\rm\longrightarrow\:10000\times\:\bigg(1+\dfrac{10}{100}\bigg)^3$

$\rm\longrightarrow\:10000\times\:\bigg(\dfrac{100+10}{100}\bigg)^3$

$\rm\longrightarrow\:10000\times\:\bigg(\dfrac{110}{100}\bigg)^3$

$\rm\longrightarrow\:10000\times\:\bigg(\dfrac{11}{10}\bigg)^3$

$\rm\longrightarrow\:10000\times\dfrac{11}{10}\times\dfrac{11}{10}\times\dfrac{11}{10}$

$\rm\longrightarrow\:10\times\:11\times\:11\times\:11$

$\rm\longrightarrow\:Rs\:13310$

Hence,the amount will be Rs 13310.

Now,

Compound Interest (CI) = Amount - Principal

Compound Interest (CI) = Rs 13310 - 10000

Compound Interest (CI) = Rs 3310

Hence,the compound interest (CI) will be 3310.

More information :-

Related to Simple interest

• SI = P × R × T/100

• Rate (r %) = SI × 100/p × t

• Time (t) = SI × 100/p × r