find the compound interest on rs. 1000 at 10% for 2 years
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13
HEY MATE HERE IS YOUR ANSWER
_______________
Principal : Rs. 1000
Rate : 10% p.a
Time : 2 years
_______________
We know
=>A = p(r + r /100})^2
✔️ A= 1000( 10 + 1/100) ^2
➡️ A = 1000 ( 11/10)^2
➡️ A = 1000 × 121/ 100
➡️ A = 1210 ₹
_______________
C. I = P - A
C. I = 1210 - 1000
C. I = 210 ₹
________________
Hope it will help you
_______________
Principal : Rs. 1000
Rate : 10% p.a
Time : 2 years
_______________
We know
=>A = p(r + r /100})^2
✔️ A= 1000( 10 + 1/100) ^2
➡️ A = 1000 ( 11/10)^2
➡️ A = 1000 × 121/ 100
➡️ A = 1210 ₹
_______________
C. I = P - A
C. I = 1210 - 1000
C. I = 210 ₹
________________
Hope it will help you
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5
Answer:
I hope it's help you
this is right answer
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