Math, asked by surajpal5742, 11 months ago

Find the compound interest on rs 60000 at the rate of 10% per annum for 1/1/2 year when interest compounded half - yearly​

Answers

Answered by isafsafiya
21

Answer:

9457.5

Step-by-step explanation:

solution

given

P= 60000

R=10%

N =1 1/2

SINCE The the rate of interest is 10% per annum,rate of inteest per conversion period (half yearly)  =5%

n ( the number of conversion period =3     (2\frac{3}{2}

∴ as we all know

A =P (1 + \frac{r}{100} ^){3}

put all the values

A = 60000(1+\frac{5}{100}) ^{3}

solve this

u will get ,

a =69457.5

now compound interst= A-P

                                       =69457.5-60000

                                        =9457.5

Answered by royalprashant50
1

Step-by-step explanation:

solution

given

P= 60000

R=10%

N =1 1/2

SINCE The the rate of interest is 10% per annum,rate of inteest per conversion period (half yearly) =5%

n ( the number of conversion period =3 (2\frac{3}{2}2

2

3

∴ as we all know

A =P (1 + \frac{r}{100} ^){3}(1+

100

r

)

3

put all the values

A = 60000(1+\frac{5}{100}) ^{3}(1+

100

5

)

3

solve this

u will get ,

a =69457.5

now compound interst= A-P

=69457.5-60000

=9457.5

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