Question

Find the compound interest on Rs 8,750 for two years at the rate of 8% per annum compounded annually and also find the difference between compound interest and simple interest.

Answer 1

P= RS 8750

T= 2 yrs

R= 8%

Now,

CI= p[ (1+R/100)^T-1 ]

=p[ (1+8/100)^2-1 ]

=p[ (1.08)^2-1 ]

=8750 [1.1664-1 ]

=8750*0.1664

= RS 1456

Again,

SI= ptr/100

= 8750*2*8/100

=140000/100

=RS 1400

Then,

Difference between ci and si

= 1456-1400

=RS 56

....hope this will helps you.....

.....! ! !.....

Answer 2

$<b>Hey mate!!! </b>$

Here is your solution ;

$Given,$
Principle(p ) = ₹8750
Rate(r) = 8%p.a.
And time(t) = 2 yrs.

Now,
$Amount= p(1 + \frac{8}{100})^2$
$A = 8750 * \frac{108} {100}^2$
$A = 10206$

Then, Ci = A - P
$= 10206 - 8750$
$= 1456$

And Si $=frac\{8750 * 8 * 2} {100}$
$Si = 1400$

Then,
Ci - Si = 1456 - 1400
=₹56

$<b><big><marquee>I hope it helps you.... </b>$