Question

Find the compound interest on rupees 1000 10% will be rs. 210 in

Answer 1

Answer:

t=2 years

Step-by-step explanation:

Given: P=1000, R=10%pa, I=210, A=P+I=1210, t=x

$a = p \times ( {1 + \frac{r}{100}) }^{t}$

$\frac{a}{p} = {(1 + \frac{r}{100}) }^{t}$

$\frac{121}{100} = ({ \frac{110}{100} })^{t}$

${ (\frac{11}{10} )}^{2} = {( \frac{11}{10}) }^{t}$

$therefore : t = 2 \: years$