find the compound interest on rupees 1000 for 2 years at 10% per annum
Answers
Answered by
1
by the formula
CI = 1000[1 +( 10÷100)] ^2
= 1000( 11÷10)^2
= 1000 * 121 ÷ 100
= 1210
hope it helps
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Answered by
0
Answer:
P= Rs 1000
T = 2yrs
R = 10%
A = P(1+R/100)raise to.n
= 1000 (1+10/100),2
= 1000× 110×110×110/100×100×100
all zero will cancel out then u will left with
= 11×11×11×10
= 13310rs.
CI = A - P
= 13310 - 1000
= Rs 12310.
HOPE THIS HELPS YOU.....
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