Question

find the compound interest on rupees 1000 for 2 years at 10% per annum​

Answer 1

by the formula

CI = 1000[1 +( 10÷100)] ^2

= 1000( 11÷10)^2

= 1000 * 121 ÷ 100

= 1210

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Answer 2

Answer:

P= Rs 1000

T = 2yrs

R = 10%

A = P(1+R/100)raise to.n

= 1000 (1+10/100),2

= 1000× 110×110×110/100×100×100

all zero will cancel out then u will left with

= 11×11×11×10

= 13310rs.

CI = A - P

= 13310 - 1000

= Rs 12310.

HOPE THIS HELPS YOU.....

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