Question

Find the compound interest on rupees 2000 for 1 and half years at 10% p.a. ,when the interest is compounded half yearly ​

Answer 1

$\huge\red{\underline{{\boxed{\textbf{QUESTION}}}}}$

Compute the compound interest on $12,000 for 2 years ate 20% p.a. when compounded half-yearly.

$\huge\red{\underline{{\boxed{\textbf{ANSWER}}}}}$

Here, P = $12,000, R = 20% and n = 2 years.

Amount after 2 years = P ( 1 + r/2) 2n= 12,000 ( 1 + 0.20/2) 2 x 2= 12,000 ( 1 + 0.1) 4

= 12,000 (1.1) 4

= 12,000 x 1.4641

Amount = $ 17569.20

∴ C.I = A - P

C.I = 17569.20 - 12000

C.I = $ 5569.2

__________________

@HarshPratapSingh

Answer 2

Answer:

Amount: Rs. 2315.25

Compound Interest: Rs. 315.25

Step-by-step explanation:

Principal: Rs. 2000

Time: 1.5 years

Rate% p.a.: 10

Since the amount is compounded half yearly, rate becomes half and time gets doubled.

New Time: 1.5 × 2 → 3 years

New Rate% p.a.: 10/2 → 5

$a \: = \: p \times \: {(1 \: + \: \frac{r}{100} )}^{n}$

2000 × (1 + 5/100)^3

→2000 × (1 + 1/20)^3

→2000 × [(20+1)/20]^3

→2000 × (21/20)^3

→2000 × 21/20 × 21/20 × 21/20

→2315.25

Amount: Rs. 2315.25

Compound Interest: Amount - Principal

→2315.25 - 2000

→315.25

Compound Interest: Rs. 315.25

Hence, Amount and Compound Interest are Rs 2315.25 and Rs. 315.25, respectively.

Hope it helped you...

Kindly Mark as Brainliest...