Question

find the compound interest on rupees 2500 @ 12% per annum for 3 years​

Answer 1

Answer:

Here is your answer

Step-by-step explanation:

here n =time

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Answer 2

Answer:

Question:-

Find the compound interest annually of rupees 2500 at 12% of rate for 3 years ?

Given:-

$\sf{:\implies{Principle = 2,500}}$

$\sf{:\implies{Rate = 12}}$%

$\sf{:\implies{Time = 3\:yrs}}$

Equation used:-

$\sf{:\implies{Compound\:Interest = P(1+\dfrac{r}{n})^{nt}-1}}$

Solution:-

$\sf{:\implies{Compound\:Interest = P(1+\dfrac{r}{n})^{nt}-1}}$

$\sf{:\implies{Compound\:Interest = 2, 500(1+\dfrac{12}{100})^{3}-1}}$

$\sf{:\implies{Compound\:Interest = 2, 500(1+0.12)^{3}-1}}$

$\sf{:\implies{Compound\:Interest = 2, 500(1.12)^{3}-1}}$

$\sf{:\implies{Compound\:Interest = 2, 500(0.404928)}}$

$\sf{:\implies{Compound\:Interest = 1,012.32}}$

$\red{\boxed{\bf{:\implies{Compound\:Interest = 1,012.32}}}}$

Hence, the compound interest annually of rupees 2500 at 12% of rate for 3 years is 1, 012.32

$\sf{:\implies{Amount = Principle + Compound\:Interest}}$

$\sf{:\implies{Amount = 2,500 + 1,012.32 }}$

$\sf{:\implies{Amount = 3,512.32 }}$

$\pink{\boxed{\bf{:\implies{Amount = 3,512.32 }}}}$