Question

find the compound interest on rupees 25000 at the 12% per annum for the three years​

Answer 1

Step-by-step explanation:

Hope it helps ...................

Answer 2

Answer:

The Compound Interest is of Rs. 10123.2

Step-by-step explanation:

Given :

Money = Rs. 25,000

Rate = 12%

For = 3 years

To find :

Compound interest

Solution :

Here -

• Principal = Rs. 25,000
• Rate = 12%
• N = 3 years

$\bigstar \: {\boxed{\sf{A= P\left( 1 + \frac{R}{100}\right)^{N}}}}$

$\sf{\implies} \: A= 25000\left( 1 + \dfrac{12}{100}\right)^{3} \\ \\ \sf{\implies} \: A=25000\left( \dfrac{112}{100}\right)^{3} \\ \\ \sf{\implies} \: A=25000\left( \dfrac{28}{25}\right)^{3} \\ \\ \sf{\implies} \: A=25000 \times \dfrac{28}{25} \times \dfrac{28}{25} \times \dfrac{28}{25} \\ \\ \sf{\implies} \: A=1000 \times \dfrac{28}{25} \times \dfrac{28}{25} \times 28 \\ \\ \sf{\implies} \: A=40 \times \dfrac{28}{25} \times 28 \times 28 \\ \\ \sf{\implies} \: A=8 \times \dfrac{28}{5} \times 28 \times 28 \\ \\ \sf{\implies} \: A= \dfrac{175616}{5} \\ \\ \sf{\implies} \: A=35123.2$

Amount = Rs. 35123.2

$\rule{300}{1.5}$

$\bigstar \: \boxed{\sf{CI = Amount - Principal}}$

$\implies \: {\sf{CI = 35123.2 - 25000}} \\ \\ \implies \: {\sf{CI = 10123.2}}$

Compound Interest = Rs. 10123.2

$\therefore$ The Compound Interest is of Rs. 10123.2