Question

find the compound interest on rupees 6400 for2 years at 5 *1/2% per annum answer is 72 3.36rs. I want step by step explanation​

Answer 1

$\huge{\sf{\boxed{\boxed{YOUR ANSWER}}}}$

TO FIND:

Compound interest on rupees 6400 for 2 years

GIVEN:

Principal amount [P]=6400

Annual rate[r]=5.2%

Time=2yrs

Thus,the amount of compound interest will be

$\red{\boxed{\green{I=P(1+100)^2-P}}}$

I=6400(1+5.2/100)²- 6400

I=6400(1+0.052)²- 6400

I=6400(1.052)²- 6400

I=7803-6400

I=683

Thus the interest of rupees 683 will be applicable for a principal amount of 6400 over a time period of 2 years

Answer 2

AnswEr :

$\bold{Given} \begin{cases}\sf{Principal=Rs. 6400} \\ \sf{Rate=5 \dfrac{1}{2} = \dfrac{11}{2} \% \: p.a.} \\ \sf{Time=2\: Yr. }\end{cases}$

• Now we will calculate the CI :

$\leadsto \sf CI = P \bigg(1 + \dfrac{r}{100} \bigg)^{t} - 1$

$\leadsto \sf CI = 6400\bigg(1 + \dfrac{11}{2 \times 100} \bigg)^{2} - 1$

$\leadsto \sf CI = 6400 \bigg(1 + \dfrac{11}{200} \bigg)^{2} - 1$

$\leadsto \sf CI = 6400\bigg( \dfrac{200 + 11}{200}\bigg)^{2} - 1$

$\leadsto \sf CI = 6400\bigg( \dfrac{211}{200}\bigg)^{2} - 1$

$\leadsto \sf CI = 6400\bigg( \dfrac{44521}{40000} - 1\bigg)$

$\leadsto \sf CI = \cancel{6400} \times \dfrac{44521 - 40000}{ \cancel{40000}}$

$\leadsto \sf CI = 8 \times \dfrac{4521}{50}$

$\leadsto \sf CI = \dfrac{36168}{50}$

$\leadsto \boxed{\sf CI = Rs. \: 723.36}$

⠀

∴ Compound Interest will be Rs. 723.36