Question

Sum of three consecutive integers is 66 . Find the integers.
Solve it with linear equation method

Answer 1

$\huge\boxed{\red{\bold{Answer}}}$

Let the number be x

x,x+1,x+2

Now according to question

$\sf x+x+1+x+2=66\\ \sf3x+3=66\\ \sf 3x=66-3\\ \sf 3x=63\\ \sf x=\frac{63}{3}\\ \sf x=21$

The value of x is 21

Then the numbers are

21,

21+1=22

21+2=23

$\boxed{\red{\bold{21,22,23}}}$

Thanks ☺️

Answer 2

Answer:

Let the even number be x

and other two consecutive numbers is

x + 2 , x + 4

According to question

x + (x + 2 ) + ( x + 4 ). = 66

3x + 6 = 66

3x = 66- 6

3x = 60

x = 60 / 3

x = 20

So , x , x +2 , x + 4

= 20 , 22, 24

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