find the compound interest on Rupees 81250 at 12% annum for 12 and half year
please help I will mark you brain list
Answers
Answer:
Given:
Present value =₹ 31250
Interest rate =8% per annum
Time =1
2
1
year =3/2 year and compounded half-yearly
To find the amount we have the formula,
Amount (A)=P(1+(r/100))
n
where P is present value, r is rate of interest, n is time in years.
Now substituting the values in above formula we get,
∴A=31250(1+(8/2)/100)
3
⇒A=31250(1+4/100)
3
⇒A=31250(1+1/25)
3
⇒A=31250(26/25)
3
⇒A=31250×17576/15625
⇒A=₹ 35152
∴ Compound interest =A–P
=35452–31250=₹ 3902
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Step-by-step explanation: PLEASE MARK AS BRAINIEST
Answer:
Amount for 12 years=P(1+12/100)^12=P(1.12)^12
Interest for 12 years =P(1.12)^12-P=P{1.12^12-P}
=P{(1.12)^12-1}
Interest for 1/2 years =P×(12/100)×(1/2)=P×0.06
Total interest for 12 and half years=
P{(1.12)^12-1+0.06}=P(3.39-1+0.06=P×2.45
=81250×2.45=199062.50 Ans
Don't do for such a big number of power 12
Main thing is for 12 years, you will use compound interest formula and for 6 months you will use simple interest formula and then will add them.