Question

Find the compound interest on the followings
perincipal = 2000
Rate% p.o =20%
Number of years =2​

Answer 1

Answer:

2000(1+20/100)^2 - 2000

2000(1+1/5)^2 -2000

2000×6/5×6/5 -2000

2000× 36/25-2000

80×36 -2000

2880 -2000

Rs 880 is Compound Interest

Answer 2

$\huge\underline\mathbb\color{gold}{SOLUTION}$

$\huge\underline\mathtt{Given:}$

Principal (P)=2000

Rate of Interest (r)=20%

Number of years (n)=2yrs

$\rule{300}{2}$

The formula of Compound Interest is

$\sf{A= P(1 + \frac{r}{100} )^{n} }$

Now,by putting the values in the formula, we get,

$\sf{ \implies A=2000(1+\frac{2}{100})^{2}}$

$\sf{\implies A=2000(\frac{120}{100})^{2}}$

$\sf{\implies A=2000×\frac{120}{100}×\frac{120}{100}}$

$\sf{\implies A= \frac{14400×20}{100}}$

$\sf{\implies A=\frac{288000}{100}}$

$\sf{A=2880}$

Hence, the required Compound Interest is

(2880-2000)

=880

$\rule{300}{2}$

$\huge\underline\mathtt\red{ThankYou}$