Question

find the compound interest when it is compound annually when principal 3200Rs, r 25% per annum and time 3 year.​

Answer 1

★ AnswEr:-

• 3050

GivEn :-

• Principal = 3200
• Rate of interest = 25%
• Time = 3 years

To Find :-

• Compound interest

Solution :-

The formula of compound interest,

• Amount - Principal

$\underline{ \boxed{ \sf{ \: C.I = P(1 + \dfrac{r}{100})^{n} - P }}}$

• C.I = Compound Interest
• P = Principal
• r = Rate of interest
• n = Time

$\implies \: { \sf{ \: C.I = 3200(1 + \dfrac{25}{100})^{3} - 3200 }}$

$\implies\sf{ \: C.I = 3200(1 + \dfrac{1}{4})^{3} - 3200}$

$\implies\sf{ \: C.I = 3200 \times ( \dfrac{5}{4} )^{3} - 3200}$

$\implies\sf{ \: C.I = 3200 \times ( \dfrac{125}{64} ) - 3200}$

$\implies\sf{ \: C.I = 3200 ( \dfrac{125}{64} - 1)}$

$\implies\sf{ \: C.I = 3200 ( \dfrac{125 - 64}{64} )}$

$\implies\sf{ \: C.I = 3200 \times \dfrac{61}{64} }$

$\implies\sf{ \: C.I =50 \times 61 }$

$\implies \underline{ \boxed{ \pink{ \sf{C.I = 3050}}}}$

Answer 2

Answer:

★ AnswEr:-

3050

GivEn :-

Principal = 3200

Rate of interest = 25%

Time = 3 years

To Find :-

Compound interest

Solution :-

The formula of compound interest,

Amount - Principal

\underline{ \boxed{ \sf{ \: C.I = P(1 + \dfrac{r}{100})^{n} - P }}}

C.I=P(1+

100

r

)

n

−P

C.I = Compound Interest

P = Principal

r = Rate of interest

n = Time

\implies \: { \sf{ \: C.I = 3200(1 + \dfrac{25}{100})^{3} - 3200 }}⟹C.I=3200(1+

100

25

)

3

−3200

\implies\sf{ \: C.I = 3200(1 + \dfrac{1}{4})^{3} - 3200}⟹C.I=3200(1+

4

1

)

3

−3200

\implies\sf{ \: C.I = 3200 \times ( \dfrac{5}{4} )^{3} - 3200}⟹C.I=3200×(

4

5

)

3

−3200

\implies\sf{ \: C.I = 3200 \times ( \dfrac{125}{64} ) - 3200}⟹C.I=3200×(

64

125

)−3200

\implies\sf{ \: C.I = 3200 ( \dfrac{125}{64} - 1)}⟹C.I=3200(

64

125

−1)

\implies\sf{ \: C.I = 3200 ( \dfrac{125 - 64}{64} )}⟹C.I=3200(

64

125−64

)

\implies\sf{ \: C.I = 3200 \times \dfrac{61}{64} }⟹C.I=3200×

64

61

\implies\sf{ \: C.I =50 \times 61 }⟹C.I=50×61

\implies \underline{ \boxed{ \pink{ \sf{C.I = 3050}}}}⟹

C.I=3050