Question

find the compound intrest for 6000 at 9% per annum for 18 months if the intrest is compounded semi-annually.​

Answer 1

Answer:

CI=1146.09

Step-by-step explanation:

P=6000

R=6%

T/N=3

$a = p(1 + \frac{r}{100} ) { }^{n}$

$a = 6000(1 + \frac{6}{100} ) {}^{3}$

$a = 7146.09$

$compound \: intrest = 7146.09 - 6000 = 1146.09$