Question

Find the compound intrest on 1,50,000 at the rate 8 per cent p.a.,compounded half yearly for
$1 \frac{1}{2} years$
​

Answer 1

Answer:

It is given that 

Principal (P) = 50000

Rate of interest (r) = 8% p.a. = 4% semi-annually

Period (n)= 121 years = 3 semi-annually

We know that 

Amount = P(1+r/100)n

Substituting the values 

= 50000(1+4/100)3

By further calculation 

= 50000(26/25)3

= 50000×26/25×26/25×26/25

= 56243.20

Here

Compound interest = A - P

Substituting the values 

= 56243.20−50000

= 6243.20

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Answer 2

$\huge \mathfrak \red{Solution:}$

$\fbox \green{Given:}$

• Principal (P) = ₹1,50,000

• Time (n) = $1 \frac{1}{2}$ years

• Rate (r) = 8%

$\fbox \pink{To find:}$

Compound interest.

$\fbox \purple{Formula:}$

Compound interest = $P[1+ \frac{R}{100}] ^{3}$

$\fbox \blue{Solved Answer:}$

• Rate=8%

• T= $\frac{3}{2}$ years

• Principal=Rs. 150000

∴ Rate = $\frac{8}{2}$ = 4% and,

Time = $\frac{3}{2}$× 2 years = 3 years

☞Compound interest:

⇒$150000[1 + \frac{4}{100}]^{3}$

⇒$150000 \times \frac{104×104×104}{100}$

⇒₹1,68,729.6

☞Now, Compound interest = Amount - Principal

⇒C.I. = ₹(1,68,728.6 - 1,50,000)

∴ C.I. = ₹ 18,729.6