Math, asked by harshitachugh1100, 1 month ago

Find the compounded ratio of (a+b)^2 : (a - b)^2, (a^2 – b^2) : (a^2 + b^2) and (a^4 - b^4) : (a+b)^4​

Answers

Answered by Avulasai
0

Answer:

1:1

Step-by-step explanation:

\frac{(a + b)^{2} }{(a-b)^{2} }  * \frac{a^{2} -b^{2} }{a^{2}+ b^{2} }  * \frac{a^{4} - b^{4}  }{(a+b)^{4} }

\frac{(a + b)^{2} }{(a-b)^{2} }  * \frac{(a + b)(a -b)}{a^{2}+ b^{2} }  * \frac{(a^{2} + b^{2})(a+b)(a-b)  }{(a+b)^{4} }

\frac{(a + b)^{4} }{(a+b)^{4} \\}

1/1

so, 1 : 1

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