Question

Find the compund Interest on₹5000 at the rate 10%p. a compounded semiannually for 3/2 years​

Answer 1

It is given that
Principal (P) = 5000
Rate of interest = 10%b p.a. or 5% half- yearly
Period (n) = 1
2
1
​
or 3 half- years
We know that
A= P(1+r/100)
n

Substituting the values
=5000(1+5/100)
3

By further calculation
= 5000×21/20×21/20×21/20
= 5788.12
Here
CI= A - P
Substituting the values
=5788.12−5000
= 788.12

Answer 2

It is given that

Principal (P) = 5000

Rate of interest = 10%b p.a. or 5% half- yearly

$Period (n) =  \: \\ 1 \times \frac{1}{2}  or \: 3 \: half- years</p><p></p><p>$

$We \: know \: that  \\ </p><p></p><p>A=   { \: P(1+r/100)}^{n} \\ </p><p></p><p>Substituting \: the \: values  \: \\ =5000 {(1 + \frac{5}{100)} }^{3} \\ </p><p>By \: further \: calculation  \\ = 5000×</p><p></p><p> \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \\ </p><p>= 5788.12</p><p></p><p> \\ Here  \\ </p><p>CI= A - P \\ </p><p>Substituting \: the \\ values \\ </p><p>=5788.12−5000 \\ </p><p>= 788.12</p><p></p><p></p><p>$