Question

find the concentration
of glucose solution which
gm / Ito
lucose Urea solution is= 180 and molecular find the concentration of
isotonic of 6.05
(Molecular weight ofglucose weight)

plz give this ans step by step I will Mark as Brainlist

of
Oreg is -
is
60 )​

Answer 1

Explanation:

Isotonic solutions have same osmotic pressure at same temperature.

\begin{lgathered}\pi_1=\pi_2\\\\\frac{n_1RT}{V_1}=\frac{n_2RT}{V_2}\\\\\frac{n_1}{V_1}=\frac{n_2}{V_2}\\\\C_1=C_2\\\\\frac{w_1}{M_1V_1}=\frac{w_2}{M_2V_2}\end{lgathered}

π

1

=π

2

V

1

n

1

RT

=

V

2

n

2

RT

V

1

n

1

=

V

2

n

2

C

1

=C

2

M

1

V

1

w

1

=

M

2

V

2

w

2

where,

n = number of moles

w = mass

M = molar mass

V = volume

R = gas constant

T = temperature

Formula used :

\frac{w_1}{M_1V_1}=\frac{w_2}{M_2V_2}

M

1

V 1

w 1 =

M 2

V 2

w 2

where,

w_1w

1

= mass of glucose = ?

V_1V

1

= volume of glucose = 1 L

M_1M

1

= molecular weight of glucose = 180 g/mole

w_2w

2

= mass of urea = 6.2 g

V_2V

2

= volume of urea = 1 L

M_2M

2

= molecular weight of urea = 60 g/mole

Now put all the given values in the above formula, we get the mass of glucose.

\frac{w_1}{180g/mole\times 1L}=\frac{6.2g}{60g/mole\times 1L}

180g/mole×1L

w

1

=

60g/mole×1L

6.2g

w_1=18.6gw

1

=18.6g

That means, 18.6 grams of glucose present in one liter of solution.

Therefore, the concentration of glucose is, 18.6 g/L