Question

find the concentration of H+,HCO3 and CO32- in a 0.01m solution of carbonic acid if PH of this is 4.18

Answer 1

Answer:

$H_{2} CO_{3} =H+ +HCO_{3} - k1,$

$HCO_{3} =H+ +CO32-;k2$

[HCO3-]=sqrt(k1*C(H2CO3)=(4.45*$10^{-7}$*0.01)^1/2

             =(4.45*10^-9)^1/2

             =6.67*10^-5 M

[H+]1=[HCO3-]=6.67*10^-5 M

[CO3-2]=sqrt(k2*C(HCO3-)=(4.69*10^-11*6.67*10^-5)^1/2

                                           =(3.13*10^-15)^1/2

                                           =5.59*10^-8 M