Find the condition that the point (x,y) may lie on the line joining (3,4)
and (-5,-6).
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Answer:
5x-4y+1=0
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Step-by-step explanation:
area of triangle will be zero
1/2(x(4-(-6))+3(-6-y)+(-5)(y-4))=0
x(10)-18-3y-5y+20=0
10x-8y+2=0
2(5x-4y+1)=0
5x-4y+1=0
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