find the condition that the zeroes of the polynomial x cube +3px square+ 3qx +rmay be in ap
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Given :
x3 + 3px2 + 3qx + r = 0
Let α , β and γ are three roots for the equation then :
By relationship between zeros and coefficient , we get
α + β + γ = - 3p ---------1
αβ + β γ + γ α = 3q ----------2
α β γ = - r ----------3
if roots α , β and γ are in AP then:
we know difference is same As :
β - α = γ - β
⇒2β = α + γ
From equation 1 , we get
⇒2β + β = - 3p
⇒β = - p --------------4
Put the value of β in equation 3 , and get
⇒α γ ( - p ) = - r
⇒α γ = rp -------------- 5
From equation 2 , we get
⇒β ( α + γ ) + rp = 3q
⇒-p (-2 p)+rp = 3q
⇒2p2 + rp = 3q
⇒2p3 + r = 3pq (answer)
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Given :
x3 + 3px2 + 3qx + r = 0
Let α , β and γ are three roots for the equation then :
By relationship between zeros and coefficient , we get
α + β + γ = - 3p ---------1
αβ + β γ + γ α = 3q ----------2
α β γ = - r ----------3
if roots α , β and γ are in AP then:
we know difference is same As :
β - α = γ - β
⇒2β = α + γ
From equation 1 , we get
⇒2β + β = - 3p
⇒β = - p --------------4
Put the value of β in equation 3 , and get
⇒α γ ( - p ) = - r
⇒α γ = rp -------------- 5
From equation 2 , we get
⇒β ( α + γ ) + rp = 3q
⇒-p (-2 p)+rp = 3q
⇒2p2 + rp = 3q
⇒2p3 + r = 3pq (answer)
Was this answer helpful4
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