Question

Find the conjugate of (2+i)*2 / 3+i in the form of a+ib​

Answer 1

Step-by-step explanation:

answer..................................

Answer 2

$=\frac{(2+i)^2}{3+i} \\=\frac{4+4i+i^2}{3+i} \\=\frac{3+4i}{3+i} \times\frac{3+i}{3+j}$

$=\frac{9-3i-4i^2+12i}{9-i^2}$

$=\frac{9-4+9i}{9-i^2} =\frac{13+9i}{10}$

$=\frac{13}{10}+\frac{9}{10}i$

It's complex conjugate is

$\frac{13}{10}-\frac{9}{10}i$

#SPJ3