Question

For two concentric circle of radius 25 cm and 7 cm the chord of the larger circle that touches the smaller circle find the length ?

Answer 1

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AB=?

In AOAC -

OA? = a? + AC²

252 = 72 + AC? =

AC? = 625 – 49 = 576

AC=24

Similarly

In AOCB -

OB? = Oc? + BC? =

252 = 72 + BC2

BC2 = 625 - 49

BC= 24

AB = AC+CB

AB = 48cm

Answer 2

Answer:

AB=?

In ΔOAC-

OA² = α² + AC²

25² = 7² + AC²

AC² = 625 − 49 = 576

AC = 24

Similarly

In ΔOCB-

OB² = OC² + BC²

25² = 7² + BC²

BC² = 625−49

BC = 24

AB = AC+CB

AB = 48cm