find the consecutive odd numbers whose product is 99
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1
hey mate
here's your answer,
let the 1st consecutive no. be x and the 2nd consecutive no. be x+2
》x(x+2)=99
》x^2+2x=99
》x^2+2x-99=0
》x^2×11x-9x-99=0
》x(x+11)-9(x+11)=0
》(x-9)(x+11)=0
hence the value of numbers be 9 and 11
here's your answer,
let the 1st consecutive no. be x and the 2nd consecutive no. be x+2
》x(x+2)=99
》x^2+2x=99
》x^2+2x-99=0
》x^2×11x-9x-99=0
》x(x+11)-9(x+11)=0
》(x-9)(x+11)=0
hence the value of numbers be 9 and 11
RohanChandru003:
wtf is this!? ha.....
Answered by
0
the consecutive odd number is 11 and 9.
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