Question

find the contact force between 2kg and 3kg block (a = 1 and F = 10 ). Justify your answer

Answer 1

Suppose force F is applied on mass m1 (=2kg) which is in contact with the mass m2 (=3kg).If the normal reaction ‘R’applied by mass ‘m1′ on mass’ m2′ and vice versa. Then for mass ‘my we have

F—R=m1 a

R=m2 a

F=(m1+m2)a

a=F/(m1+m2)=10/(2+3)

=2m/s^2

Reaction between the two blocks, R=m2 a

=(3×2) N

=6 N

Other method÷
you can use momentum p=m.a
p=m*(v-u)/t