find the continued product: (2p+3)(2p-3)(4p2+9)
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Answered by
27
Answer:
(2p+3) (2p-3) (4p^2 + 9)
using a^2- b^2 = (a+b) (a-b)
(4p^2 - 9) (4p^2 + 9)
using a^2- b^2 = (a+b) (a-b)
(4p^2)^2 - (9)^2
FINAL ANSWER=>== 16p^4 - 81
Answered by
4
Answer:
16p⁴-81
Step-by-step explanation:
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