Question

Find the coordinate matrix of the vector (1,0,1) in the basis of C^3 consisting of the vectors (2i, 1,0), (2,-1,1), (0,1+i, 1-i), in that order. ​

Answer 1

Answer:

(1,1,0) = x (1,1,1) + y (0,1,1) + z (1,1,2)

x + z = 1

x + y + z = 1

x + y + 2z = 0

Subtracting the first equation from the second gives

y = 0

For this value of y the third equation becomes

x + 2z = 0

Subtracting the first equation from this gives

z = -1

Then plugging this value of z into the first equation we get

x - 1 = 1 so

x = 2.

So we can write (1,1,0) as a linear combination of the basis vectors as follows:

(1,1,0) = 2 (1,1,1) + 0 (0,1,1) - 1 (1,1,2)

plese tell me the truth are you ankita 's friend? you know ankita???please friend tell me the truth...

Answer 2

Answer:

hope it is help

ok n .

have a good day.

gm