Question

Find the coordinate of a point which divides the
line AB, A (1, 3), B (2,-1) in the ratio 3:2
internally.​

Answer 1

Answer:

Using the section formula, if a point (x,y) divides the line joining the points (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+nx

1

,

m+n

my

2

+ny

1

)

Let (h,k) be the point which divides the line segment joining points (1,−3) and (−3,9) in the ratio 1:3 internally.

By section formula,

(h,k)=(

3+1

1×3+1×(−3)

,

1+3

−3×3+9×1

)=(0,0)

Hence the origin divides the line segment joining points (1,−3) and (−3,9) in the ratio 1:3 internally.