find the coordinate of centre of curvature at a point od parabola y²=4ax. Hence show that its evolute is 270y²=
4(x-20)³
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you do all i just directions you ok...
first you put the value of y² in the second equation and you break the (x-20)³ .use the rule is (a-b)³=a³-b³-3a²b+3ab².
and calculated ..and last time you find you ans ok.......gd nit
first you put the value of y² in the second equation and you break the (x-20)³ .use the rule is (a-b)³=a³-b³-3a²b+3ab².
and calculated ..and last time you find you ans ok.......gd nit
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