Question

find the coordinate of circumcente of the triangle whose vetices are A(4,3),B(-2,3)and C(6,-1)
$pls \: answer$
​

Answer 1

Line perpendicular to AB & passing thro ' B

2x - y = 13

Line perpendicular to AC & passing thro C ( 4,3 ) is X - 4 = 0

These two intersect at ( 4 , -5 )

So eqn of circle with ( -2,3 ) & 4 , -5 ) as end ponts of is ( x + 2 ) ( x - 4 ) + ( y - 3 ) ( y + 5 ) = 0

Or x ^ 2 + y ^ 2 -2x + 2y –23 = 0

Circumcentre (1 -1)