Find the coordinate of the point equidistant from the three given point A(5,1),k B(-3,-7) and C(7,-1)
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Answered by
1
Let the co-ordinate of required = p(x, y)
so,P (x, y) = 5+(-3) +7 / 3
= 9/3 = 3
And, y coordinate = 1+(-7)+(-1)/3
= -7/3
so, P (3 ,-7/3)
______________
☺☺
so,P (x, y) = 5+(-3) +7 / 3
= 9/3 = 3
And, y coordinate = 1+(-7)+(-1)/3
= -7/3
so, P (3 ,-7/3)
______________
☺☺
Answered by
1
hey..
→ x=2 , y= -4
→ D(2,-4)
★ refer to the attachment.
→ x=2 , y= -4
→ D(2,-4)
★ refer to the attachment.
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