Question

find the coordinate of the point of trisection of the line segment joining the points A(7,-2)and B(1,-5)

Answer 1

this can be done by using section formula

Answer 2

Answer:

(5,-3)

Step-by-step explanation:

Let the point of trisection be C

This point divides the line in the ratio 1: 2

AC:CB = 1:2

Refer the attached figure

So, we will use section formula:

$x=\frac{mx_2+nx_1}{m+n} , y=\frac{my_2+ny_1}{m+n}$

$A=(x_1,y_1)=(7,-2)$

$B=(x_2,y_2)=(1,-5)$

m:n=1:2

Substitute the values in the section formula:

$x=\frac{1(1)+2(7)}{1+2} , y=\frac{1(-5)+2(-2)}{1+2}$

$x=\frac{15){3} , y=\frac{-9}{3}$

$x=5 , y=-3$

So, the coordinate of the point of trisection of the line segment joining the points A(7,-2)and B(1,-5) is (5,-3)