Question

Find the coordinate of the point p (a,b) where the ordinate is twice as much as abscissa and sum of the coordinate is -12

Answer 1

Step-by-step explanation:

let the absicca be x

ordinate =2x

absicca =x

2x+x= -12

3x = -12

x= -12/3

( x =-4)

ordinate= 2(-4)=-8

absicca= -4