Find the coordinates of a point A,where AB is the diameter of a circle whose centre is (2,-3) and B is (1, 4) *
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Coordinates of A is (3,10)
Step-by-step explanation:
1. Draw XY plane and denote center (suppose O) and point B on plane.
2. B is in first and center is in 4th quadrant, slope of BO is negative so A will be in 4th quadrant.
3. Now use trigonometry between two triangle formed by (A,O,C) and (A,B,D)
4. For point C draw vertical line from B and horizontal line from O, intersection point will be C
5. For point D draw vertical line from B and horizontal line from assumed A
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sorry I don't know the answer
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