Question

Find the coordinates of a point on the x axis which is equidistant from the points a bracket 2, - 5 and b bracket

Answer 1

Let the point of x-axis be P(x, 0) Given A(2, -5) and B(-2, 9) are equidistant from P That is PA = PB Hence PA2 = PB2 → (1) Distance between two points is √[(x2 - x1)2 + (y2 - y1)2] PA = √[(2 - x)2 + (-5 - 0)2] PA2 = 4 - 4x +x2 + 25 = x2 - 4x + 29 Similarly, PB2 = x2 + 4x + 85 Equation (1) becomes x2 - 4x + 29 = x2 + 4x + 85 - 8x = 56 x = -7 Hence the point on x-axis is (-7, 0)

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