Question

find the coordinates of a point on y-axis which are at the distance of 13 unit from the point (5,6)​

Answer 1

Let the point on y-axis be (0,a)

According to the question⇒

(0−5)

2

+(a−14)

2

=13

⇒25+a

2

+196−28a=169

⇒a

2

−28a+52=0

a=

2

28±

(28)

2

−4×52

=

2

28±

784−208

=

2

28±

576

=

2

28±24

a=

2

28+24

&

2

28−24

=

2

52

=26

2

4

=2

∴a=26,2